Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

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71.

If 1 - cosxcsc2xdx = fx + c, then fx is equal to 

  • tanx2

  • cotx2

  • 2tanx2

  • 12tanx2


A.

tanx2

1 - cosxcsc2xdx 2sin2x2 . 1sin2xdx  cosx = 1 - 2sin2x2= 2  sin2x22sinx2cosx2   sinx = 2sinx2cosx2= 2sinx2cosx22 . 2sin2x2 . cos2x2dx= 12sec2x2dx = 12tanx2 . 2 + c= tanx2 + c = fx + c fx = tanx2= fx + c


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72.

If In = 0nπ4tanxdx, thenI2 + I4, I3 + I5, I4 + I6, . . . , are in

  • arithmatic progression

  • geometric progression

  • harmonic progression

  • arithmetic-geometric progression


73.

The area (in square units) of the region enclosed by the two circles x2 + y2 = 1 and (x - 1)2 + y2 = 1 is

  • 2π3 + 32

  • π3 + 32

  • π3 - 32

  • 2π3 - 32


74.

The values of a function f(x) at different values of x are as follows

x 0 1 2 3 4 5
f(x) 2 3 6 11 18 27

Then, the approximate area (in square units) bounded by the curve y = f(x) and x-axis between x = 0 and 5, using the Trapezoidal rule, is

  • 50

  • 75

  • 52.5

  • 62.5


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75.

The solution of tanydydx = sinx + y + sinx - y is

  • sec(y) = 2cos(x) + c

  • sec(y) = - 2cos(x) + c

  • tan(y) =  - 2cos(x) + c

  • sec2(y) = - 2cos(x) + c


76.

A family of curves has the differential equation xydydx = 2y2 - x2. Then, the family of curves is

  • y2 = cx2 + x3

  • y2 = cx4 + x3

  • y2 = x + cx4

  • y2 = x2 + cx4


77.

The length of the common chord of the circles of radii 15 and 20, whose centres are 25 unit of distance apart, is

  • 12

  • 16

  • 24

  • 25


78.

Let M be the foot of the perpendicular from a point P on the parabola y = 8(x - 3) onto its directrix and let S be the focus ofthe parabola. If  SPM is an equilateral triangle, then P is equal to

  • (43, 8)

  • (8, 43)

  • (9, 43)

  • (43, 9)


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79.

The point dividing the join of (3, - 2, 1) and( - 2, 3 11) in the ratio 2 : 3 is

  • (1, 1, 4)

  • (1, 0, 5)

  • (2, 3, 5)

  • (0, 6, - 1)


80.

The longest distance of the point (a, 0) from the curve 2x2 + y= 2x is

  • 1 + a

  • 1 - a

  • 1 - 2a +2a2

  • 1 - 2a + 3a2


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