If Q(0, - 1, - 3) is the image P in the plane 3x - y + 4z - 2 = 0 and R is the point (3, - 1, - 2). Then the area (in sq. units) of PQR is :
912
213
652
B.
x1 - 03 = y1 + 1- 1 = z1 + 34 = - 21 - 12 - 29 + 1 + 16⇒ Px1, y1, z1 = 3, - 2, 1, Q = 0, - 1, 3 and R = 3, - 1, - 2Area of ∆PQR = 12PQ × PR = 912 sq. units
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