The length of the base of an isosceles triangle is 2x - 2y + 4z, and its perimeter is 4x - 2y + 6z. Then the length of each of the equal sides is:
x + y
x + y + z
2(x + y)
x + z
D.
x + z
BC (Base of isosceles triangle) = 2x - 2y + 4z
Perimeter = 4x - 2y + 6z.
Let AB = AC = a (Sides of an isosceles triangle are equal)
According to the question,
AB + AC + BC = 4x - 2y + 6z
a + a + 2x - 2y + 4z = 4z - 2y + 6z
2a = 2x + 2z
a = x + z
Visitors to a show were charged ₹ 15 each on the first day, ₹ 7.50 on the second day, ₹ 2.50 on the third day and total attendance on three days were in the ratio 2 : 5 : 13 respectively. The average charge per person for the entire three day is
₹ 5
₹ 5.50
₹ 6
₹ 7
In Δ PQR, L and M are two points on the sides PQ and PR respectively such that LM || QR. If PL = 2 cm, LQ = 6 cm and PM = 1.5 cm, then MR in cm is
0.5
4.5
9
8
The length of the radius of a circle with centre O is 5 cm and the length of the chord AB is 8 cm. The distance of the chord AB from the point O is
2 cm
3 cm
4 cm
15 cm
The upper part of a tree broke at a certain height makes an angle of 60° with the ground at a distance of 10 m from its feet. The original height of the tree was
20√3 m
10√3 m
10(2 + √3) m
10(2 - √3) m
What would be the compound interest of ₹ 25,000/- for 2 years at 5% per annum?
₹ 2,500
₹ 2,562.5
₹ 2,425.25
₹ 5,512.5